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\OT1/cmr/m/it/10.95 where $[][]$ is the $\OML/cmm/m/it/10.95 i$\OT1/cmr/m/it/10
.95 -th com-po-nent of vec-tor $[][]$. We also de-fine $\OMS/cmsy/m/n/10.95 N[]
\OT1/cmr/m/n/10.95 (\OML/cmm/m/it/10.95 f; ^^O; n\OT1/cmr/m/n/10.95 ) = [][] \O
MS/cmsy/m/n/10.95 N[]\OT1/cmr/m/n/10.95 (\OML/cmm/m/it/10.95 f; ^^O; X[]\OT1/cm
r/m/n/10.95 )$\OT1/cmr/m/it/10.95 . 
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\OMS/cmsy/m/n/10.95 N[]\OT1/cmr/m/n/10.95 (\OML/cmm/m/it/10.95 L[]; ^^O=\OT1/cm
r/m/n/10.95 2\OML/cmm/m/it/10.95 ; n\OT1/cmr/m/n/10.95 ) \OMS/cmsy/m/n/10.95 ^^
A N[]\OT1/cmr/m/n/10.95 (\OML/cmm/m/it/10.95 L[]; ^^O=\OT1/cmr/m/n/10.95 2\OML/
cmm/m/it/10.95 ; n\OT1/cmr/m/n/10.95 )$. There-fore we only need to show that $
[][]([]) \OMS/cmsy/m/n/10.95 ^^T [][]\OT1/cmr/m/n/10.95 ([]) +
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\OT1/cmr/m/n/10.95 To see this, con-sider a func-tion $\OML/cmm/m/it/10.95 ^^K[
]$ \OT1/cmr/m/n/10.95 such that $\OML/cmm/m/it/10.95 ^^K[]\OT1/cmr/m/n/10.95 (\
OML/cmm/m/it/10.95 Y[]\OT1/cmr/m/n/10.95 )$ is a pa-ram-e-ter that sat-is-fies 
$\OML/cmm/m/it/10.95 E[]f[]\OT1/cmr/m/n/10.95 (\OMS/cmsy/m/n/10.95 L\OT1/cmr/m/
n/10.95 (\OML/cmm/m/it/10.95 ^^K[]; []\OT1/cmr/m/n/10.95 )) \OMS/cmsy/m/n/10.95
 ^^@
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